Lesson 16
Weighted Averages in a Triangle
Problem 1
Triangle \(ABC\) and its medians are shown.
Select all statements that are true.
The medians intersect at \(\left(\frac{1}{3}, 2\right)\).
The medians and altitudes are the same for this triangle.
An equation for median \(AE\) is \(y=\frac{6}{7}(x+2)\).
Point \(G\) is \(\frac{2}{3}\) of the way from \(A\) to \(E\).
Median \(BF\) is congruent to median \(CD\).
Solution
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Problem 2
Triangle \(ABC\) has vertices at \((\text-2,0), (\text-1,6),\) and \((6,0)\). What is the point of intersection of the triangle’s medians?
Solution
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Problem 3
Triangle \(EFG\) and its medians are shown.
Match each pair of segments with the ratios of their lengths.
Solution
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Problem 4
Given \(A=(\text-3,2)\) and \(B=(7,\text-10)\), find the point that partitions segment \(AB\) in a \(1:4\) ratio.
Solution
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(From Unit 6, Lesson 15.)Problem 5
Graph the image of quadrilateral \(ABCD\) under a dilation using center \(A\) and scale factor \(\frac{1}{3}\).
Solution
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(From Unit 6, Lesson 15.)Problem 6
A trapezoid is a quadrilateral with at least one pair of parallel sides. Show that the quadrilateral formed by the vertices \((0,0), (5,2), (10,10),\) and \((0,6)\) is a trapezoid.
Solution
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(From Unit 6, Lesson 14.)Problem 7
Here are the graphs of the circle centered at \((0,0)\) with radius 6 units and the line given by \(2x+y=11\). Determine whether the circle and the line intersect at the point \((3,5)\). Explain or show your reasoning.
Solution
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(From Unit 6, Lesson 13.)Problem 8
A parabola has focus \((\text-3,2)\) and directrix \(y=\text-3\). The point \((a,5)\) is on the parabola. How far is this point from the focus?
8 units
5 units
3 units
2 units
Solution
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(From Unit 6, Lesson 8.)