Lesson 15
Solving Systems by Elimination (Part 2)
- Let’s think about why adding and subtracting equations works for solving systems of linear equations.
15.1: Is It Still True?
Here is an equation: \(50 + 1 = 51\).
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Perform each of the following operations and answer these questions: What does each resulting equation look like? Is it still a true equation?
- Add 12 to each side of the equation.
- Add \(10 + 2\) to the left side of the equation and 12 to the right side.
- Add the equation \(4 + 3 = 7\) to the equation \(50 + 1 = 51\).
- Write a new equation that, when added to \(50 +1 = 51\), gives a sum that is also a true equation.
- Write a new equation that, when added to \(50 +1 = 51\), gives a sum that is a false equation.
15.2: Classroom Supplies
A teacher purchased 20 calculators and 10 measuring tapes for her class and paid \$495. Later, she realized that she didn’t order enough supplies. She placed another order of 8 of the same calculators and 1 more of the same measuring tape and paid \$178.50.
This system represents the constraints in this situation:
\(\begin{cases} \begin {align}20c + 10m &= 495\\ 8c + \hspace{4.5mm} m &= 178.50 \end{align}\end{cases}\)
- Discuss with a partner:
- In this situation, what do the solutions to the first equation mean?
- What do the solutions to the second equation mean?
- For each equation, how many possible solutions are there? Explain how you know.
- In this situation, what does the solution to the system mean?
- Find the solution to the system. Explain or show your reasoning.
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To be reimbursed for the cost of the supplies, the teacher recorded: “Items purchased: 28 calculators and 11 measuring tapes. Amount: \$673.50.”
- Write an equation to represent the relationship between the numbers of calculators and measuring tapes, the prices of those supplies, and the total amount spent.
- How is this equation related to the first two equations?
- In this situation, what do the solutions of this equation mean?
- How many possible solutions does this equation have? How many solutions make sense in this situation? Explain your reasoning.
15.3: A Bunch of Systems
Solve each system of equations without graphing and show your reasoning. Then, check your solutions.
A\(\begin {cases} \begin {align}2x + 3y &= \hspace {2mm}7\\ \text-2x +4y &= 14 \end {align} \end {cases} \)
B\(\begin {cases} \begin {align}2x + 3y &= \hspace {2mm}7\\ 3x -3y &= 3 \end {align} \end {cases} \)
C\(\begin {cases} \begin {align}2x + 3y &= 5\\ 2x +4y &= 9 \end {align} \end {cases}\)
D\(\begin {cases} \begin {align}2x + 3y &=16\\ 6x -5y &= 20 \end {align} \end {cases}\)
This system has three equations: \(\begin{cases}3 x + 2y - z = 7 \\ \text{-} 3x + y +2z =\text- 14 \\ 3x+y-z=10 \end{cases}\)
- Add the first two equations to get a new equation.
- Add the second two equations to get a new equation.
- Solve the system of your two new equations.
- What is the solution to the original system of equations?
Summary
When solving a system with two equations, why is it acceptable to add the two equations, or to subtract one equation from the other?
Remember that an equation is a statement that says two things are equal. For example, the equation \(a = b\) says a number \(a\) has the same value as another number \(b\). The equation \(10 + 2 = 12\) says that \(10+2\) has the same value as 12.
If \(a = b\) and \(10 + 2 = 12\) are true statements, then adding \(10+2\) to \(a\) and adding \(12\) to \(b\) means adding the same amount to each side of \(a=b\). The result, \(a + 10 + 2 = b + 12\), is also a true statement.
As long as we add an equal amount to each side of a true equation, the two sides of the resulting equation will remain equal.
We can reason the same way about adding variable equations in a system like this:
\(\begin {cases} \begin {align} e + f = 17\\ \text-2e + f =\text-1 \end{align}\end {cases}\)
In each equation, if \((e,f)\) is a solution, the expression on the left of the equal sign and the number on the right are equal. Because \(\text-2e+f\) is equal to -1:
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Adding \(\text-2e + f\) to \(e+f\) and adding -1 to 17 means adding an equal amount to each side of \(e+f=17\). The two sides of the new equation, \(\text-e + 2f = 16\), stay equal.
The \(e\)- and \(f\)-values that make the original equations true also make this equation true.
\(\begin {align} e +\hspace{2mm} f &= 17\\ \text-2e +\hspace{2mm} f &=\hspace{0.8mm}\text-1 \quad+\\ \overline {\hspace{2mm}\text-e + 2f }& \overline{ \hspace{1mm}=16} \end {align}\)
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Subtracting \(\text-2e + f\) from \(e+f\) and subtracting -1 from 17 means subtracting an equal amount from each side of \(e+f=17\). The two sides of the new equation, \(3e = 18\), stay equal.
The \(f\)-variable is eliminated, but the \(e\)-value that makes both the original equations true also makes this equation true.
\(\begin {align} e +\hspace{2mm} f &= 17\\ \text-2e +\hspace{2mm} f &=\hspace{0.8mm}\text-1 \quad-\\ \overline{\hspace{0.8mm}3e \hspace{9.5mm}} &\overline{\hspace{1mm}=18} \end {align}\)
From \(3e = 18\), we know that \(e=6\). Because 6 is also the \(e\)-value that makes the original equations true, we can substitute it into one of the equations and find the \(f\)-value.
The solution to the system is \(e=6, f=11\), or the point \((6,11)\) on the graphs representing the system. If we substitute 6 and 11 for \(e\) and \(f\) in any of the equations, we will find true equations. (Try it!)
Glossary Entries
- elimination
A method of solving a system of two equations in two variables where you add or subtract a multiple of one equation to another in order to get an equation with only one of the variables (thus eliminating the other variable).
- solution to a system of equations
A coordinate pair that makes both equations in the system true.
On the graph shown of the equations in a system, the solution is the point where the graphs intersect.
- substitution
Substitution is replacing a variable with an expression it is equal to.
- system of equations
Two or more equations that represent the constraints in the same situation form a system of equations.