Lesson 11

Finding Distances in the Coordinate Plane

Let’s find distances in the coordinate plane.

11.1: Closest Distance

  1. Order the following pairs of coordinates from closest to farthest apart. Be prepared to explain your reasoning.

    1. \((2,4)\) and \((2,10)\)

    2. \((\text -3,6)\) and \((5,6)\)

    3. \((\text -12, \text -12)\) and \((\text -12, \text -1)\)

    4. \((7, 0)\) and \((7,\text -9)\)

    5. \((1, \text -10)\) and \((\text -4,\text -10)\)

  2. Name another pair of coordinates that would be closer together than the first pair on your list.

  3. Name another pair of coordinates that would be farther apart than the last pair on your list.

11.2: How Far Apart?

Find the distances between the three points shown.

xy plane, 3 points plotted. -14 comma 9, -14 comma -3, 16 comma -3

 

11.3: Perimeters with Pythagoras

  1. Which figure do you think has the longer perimeter?

  2. Select one figure and calculate its perimeter. Your partner will calculate the perimeter of the other. Were you correct about which figure had the longer perimeter?
Two triangles labeled “J” and “K” are graphed in the coordinate plane with the origin labeled “O”. 



Quadrilateral \(ABCD\) has vertices at \(A=(\text -5,1)\), \(B=(\text -4,4)\), \(C=(2,2)\), and \(D=(1,\text -1)\).

  1. Use the Pythagorean Theorem to find the lengths of sides \(AB\), \(BC\), \(CD\), and \(AD\).
  2. Use the Pythagorean Theorem to find the lengths of the two diagonals, \(AC\) and \(BD\).

  3. Explain why quadrilateral \(ABCD\) is a rectangle.

11.4: Finding the Right Distance

Have each person in your group select one of the sets of coordinate pairs shown here. Then calculate the length of the line segment between those two coordinates. Once the values are calculated, have each person in the group briefly share how they did their calculations.

  • \((\text -3,1)\) and \((5,7)\)

  • \((\text -1,\text -6)\) and \((5,2)\)

  • \((\text -1,2)\) and \((5,\text -6)\)

  • \((\text -2,\text -5)\) and \((6,1)\)

  1. How does the value you found compare to the rest of your group?

  2. In your own words, write an explanation to another student for how to find the distance between any two coordinate pairs.

Summary

We can use the Pythagorean Theorem to find the distance between any two points on the coordinate plane. For example, if the coordinates of point \(A\) are \((\text-2,\text-3)\), and the coordinates of point \(B\) are \((\text-8,4)\), let’s find the distance between them. This distance is also the length of line segment \(AB\). It is a good idea to plot the points first.

The graph of a line segment in the coordinate plane with the origin labeled “O”. 

Think of the distance between \(A\) and \(B\), or the length of segment \(AB\), as the hypotenuse of a right triangle. The lengths of the legs can be deduced from the coordinates of the points.

A triangle is graphed in the coordinate plane with the origin labeled “O”. 

The length of the horizontal leg is 6, which can be seen in the diagram, but it is also the distance between the \(x\)-coordinates of \(A\) and \(B\) since \(|\text-8-\text-2|=6\). The length of the vertical leg is 7, which can be seen in the diagram, but this is also the distance between the \(y\)-coordinates of \(A\) and \(B\) since \(|4 - \text-3|=7\).

Once the lengths of the legs are known, we use the Pythagorean Theorem to find the length of the hypotenuse, \(AB\), which we can represent with \(c\). Since \(c\) is a positive number, there is only one value it can take:

\(\begin{align} 6^2+7^2&=c^2 \\ 36+49&=c^2 \\ 85&=c^2 \\ \sqrt{85}&=c \\ \end{align}\)

This length is a little longer than 9, since 85 is a little longer than 81. Using a calculator gives a more precise answer, \(\sqrt{85} \approx 9.22\).

Video Summary

Video VLS G8U8V4 Using the Pythagorean Theorem (Lessons 9–11) available at https://player.vimeo.com/video/526969582.

Glossary Entries

  • Pythagorean Theorem

    The Pythagorean Theorem describes the relationship between the side lengths of right triangles.

    The diagram shows a right triangle with squares built on each side.  If we add the areas of the two small squares, we get the area of the larger square.

    The square of the hypotenuse is equal to the sum of the squares of the legs. This is written as \(a^2+b^2=c^2\).

    a right triangle with squares built on each side
  • hypotenuse

    The hypotenuse is the side of a right triangle that is opposite the right angle. It is the longest side of a right triangle.

    Here are some right triangles. Each hypotenuse is labeled.

    Four right triangles of different sizes and orientations each with two legs and a hypotenuse opposite the right angle.
  • legs

    The legs of a right triangle are the sides that make the right angle. 

    Here are some right triangles. Each leg is labeled.

    Four right triangles of different sizes and orientations each with two legs and a hypotenuse opposite the right angle.