Unit 5 Family Materials

Here are the video lesson summaries for Grade 6, Unit 5: Arithmetic in Base Ten. Each video highlights key concepts and vocabulary that students learn across one or more lessons in the unit. The content of these video lesson summaries is based on the written Lesson Summaries found at the end of lessons in the curriculum. The goal of these videos is to support students in reviewing and checking their understanding of important concepts and vocabulary. Here are some possible ways families can use these videos:

• Keep informed on concepts and vocabulary students are learning about in class.
• Watch with their student and pause at key points to predict what comes next or think up other examples of vocabulary terms (the bolded words).
• Consider following the Connecting to Other Units links to review the math concepts that led up to this unit or to preview where the concepts in this unit lead to in future units.

Grade 6, Unit 5: Arithmetic in Base Ten	Vimeo	YouTube
Video 1: Adding and Subtracting Decimals (Lessons 2–4)	Link	Link
Video 2: Multiplying Decimals (Lessons 5–8)	Link	Link
Video 3: Dividing Whole Numbers (Lessons 9–10)	Link	Link
Video 4: Dividing Decimals (Lessons 11–14)	Link	Link

Video 1

Video 2

Video 3

Video 4

This week, your student will add and subtract numbers using what they know about the meaning of the digits. In earlier grades, your student learned that the 2 in 207.5 represents 2 hundreds, the 7 represents 7 ones, and the 5 represents 5 tenths. We add and subtract the digits that correspond to the same units like hundreds or tenths. For example, to find \(10.5 + 84.3\), we add the tens, the ones, and the tenths separately, so \(10.5 + 84.3 = 90 + 4 + 0.8 = 94.8\).

Any time we add digits and the sum is greater than 10, we can “bundle” 10 of them into the next higher unit. For example, \(0.9 + 0.3 = 1.2\).

To add whole numbers and decimal numbers, we can arrange \(0.921 + 4.37\) vertically, aligning the decimal points, and find the sum. This is a convenient way to be sure we are adding digits that correspond to the same units. This also makes it easy to keep track when we bundle 10 units into the next higher unit (some people call this “carrying”).

Here is a task to try with your student:

Find the value of \(6.54 + 0.768\).

Solution: 7.308.  Sample explanation: there are 8 thousandths from 0.768. Next, the 4 hundredths from 6.54 and 6 hundredths from 0.768 combined make 1 tenth. Together with the 5 tenths from 6.54 and the 7 tenths from 0.768 this is 13 tenths total or 1 and 3 tenths. In total, there are 7 ones, 3 tenths, no hundredths, and 8 thousandths.

This week, your student will multiply decimals. There are a few ways we can multiply two decimals such as \((2.4) \boldcdot (1.3)\). We can represent the product as the area of a rectangle. If 2.4 and 1.3 are the side lengths of a rectangle, the product \((2.4) \boldcdot (1.3)\) is its area. To find the area, it helps to decompose the rectangle into smaller rectangles by breaking the side lengths apart by place value. The sum of the areas of all of the smaller rectangles, 3.12, is the total area.

Here is a task to try with your student:

Find \((2.9) \boldcdot (1.6)\) using an area model and partial products.

Solution: 4.64. The area of the rectangle (or the sum of the partial products) is: \(2 + 0.9 + 1.2 + 0.54 = 4.64\)

This week, your student will divide whole numbers and decimals. We can think about division as breaking apart a number into equal-size groups.

For example, consider \(65 \div 4\). We can image that we are sharing 65 grams of gold equally among 4 people. Here is one way to think about this:

• First give everyone 10 grams. Then 40 grams have been shared out, and 25 grams are left over. We can see this in the first example.
• If we give everyone 6 more grams, then 24 grams have been shared out, and 1 gram is left.
• If we give everyone 0.2 more grams, then 0.8 grams are shared out and 0.2 grams are left.
• If everyone gets 0.05 more grams next, then all of the gold has been shared equally.

Everyone gets \(10 + 6 + 0.2 + 0.05 = 16.25\) grams of gold.

The calculation on the right shows different intermediate steps, but the quotient is the same. This approach is called the partial quotients method for dividing.

Here is a task to try with your student:

Here is how Jada found \(784 \div 7\) using the partial quotient method.​​

1. In the calculation, what does the subtraction of 700 represent?
2. Above the dividend 784, we see the numbers 100, 10, and 2. What do they represent?
3. How can we check if 112 if the correct quotient for \(784 \div 7\)? 

Solution

1. Subtraction of 7 groups of 100 from 784.
2. 100, 10, and 2 are the amounts distributed into each group over 3 rounds of dividing.
3. We can multiply \(7 \boldcdot 112\) and see if it produces 784.